-7/((3x^2+x-4))

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Solution for -7/((3x^2+x-4)) equation: 


D( x )

3*x^2+x-4 = 0

3*x^2+x-4 = 0

3*x^2+x-4 = 0

3*x^2+x-4 = 0

DELTA = 1^2-(-4*3*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(2*3) or x = (-49^(1/2)-1)/(2*3)

x = 1 or x = -4/3

x in (-oo:-4/3) U (-4/3:1) U (1:+oo)

-7/(3*x^2+x-4) = 0

3*x^2+x-4 = 0

3*x^2+x-4 = 0

DELTA = 1^2-(-4*3*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(2*3) or x = (-49^(1/2)-1)/(2*3)

x = 1 or x = -4/3

(x+4/3)*(x-1) = 0

-7/((x+4/3)*(x-1)) = 0

x belongs to the empty set

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